Hello,
I would like to put a second order polynomial function through 9 points. The points are given in the form P(x,y,z).
Goal:
(1) Calculate polynomial function
(2) Calculate the mean curvature (= second derivative) of the function
Is there something similar to "p = polyfit(x,y,z,n)"?
Remark:
I can put a circle through three points in space and calculate the corresponding curvature of the circle. For this I use "circlefit3d(p1,p2,p3)". But I don't want to use only 3 of the 9 points for the curvature calculation.
I would be very pleased about a feedback.

댓글 수: 3

Bjorn Gustavsson
Bjorn Gustavsson 2021년 1월 29일
Question to you: Is the curvature constant along a polynomial?
Christoph Thorwartl
Christoph Thorwartl 2021년 1월 29일
3D markers were fixed on the surface of an object (in a row). A force is applied to the object which causes it to bend. The bending line does not have a completely homogeneous curvature.
Christoph Thorwartl
Christoph Thorwartl 2021년 1월 29일
Picture see attached.

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Bjorn Gustavsson
Bjorn Gustavsson 2021년 1월 29일

1 개 추천

You have the file exchange contribution polyfitn that should do what you want.
HTH

추가 답변 (1개)

Walter Roberson
Walter Roberson 2021년 1월 29일

1 개 추천

Is there something similar to "p = polyfit(x,y,z,n)"?
No. However, polyfit() constructs the Vandermode companion matrix and then uses \ for linear least squared computation of the coefficients. You can do the same thing;
X = x(:); Y = Y(:); Z = Z(:);
A = [X.^2, X.*Y, Y.^2, X, Y, ones(size(X))];
b = Z;
A\b
Assuming a*x^2 + b*x*y + c*y^2 + d*x + e*y + f = z .
In particular, assuming that there is no z^2 or x*z or y*z .
If there are higher order z, then at the moment I am not sure how to set up the problem without ending up with a companion matrix and all zeros on the right hand side, which unfortunately leads you to an all-zero solution instead of something useful.

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Christoph Thorwartl
Christoph Thorwartl 2021년 1월 29일
Thank you very much for your answer. I will now look at both approaches in detail.

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