To find aspect ratio of an image using matlab

I have done code to find aspect ration of an image, but i didn't get the actual value some time.Is the code correct to find aspect ratio,If not please tell me the alternate way to solve the problem. Thank you.

srcFiles = dir('C:\Users\meghnad\Desktop\New folder\*.jpg');

 for i = 1 : length(srcFiles)

filename = strcat('C:\Users\meghnad\Desktop\New folder\',srcFiles(i).name);

 E = imread(filename);

 level = graythresh(E);

BW = im2bw(E,level);

 [m,n]=size(BW);

 AR=m/n

 end

Answer 1

[Iman Ansari]

Hi. I think n/m:

E = imread('peppers.png');
m=size(E,1);
n=size(E,2);
AR=n/m

[Jagdeep]

hi i am new to matlab. Can you please tell how your above statements work particularly from 2 to 4.

[Image Analyst]

It gives you the size of the dimensions, with dimension 1 being rows, dimension 2 being columns. AR is the ratio of the number of columns to the number of rows, which is the aspect ratio.