Compare for uniqueness between 2 very large matrices

조회 수: 11 (최근 30일)
Koren Murphy
Koren Murphy 2021년 1월 13일
편집: Adam Danz 2021년 1월 15일
I have two matrices of the same size - 95 x 100,000.
They are in different orders but I would like to compare if columns in one matrix are repeated elsewhere in the other matrix - or if the 2 matrices are completely unique?
  댓글 수: 2
Iuliu Ardelean
Iuliu Ardelean 2021년 1월 13일
You can use Lia = ismember(A,B,'rows'), which returns a vector of ones and zeros of length(A), representing those rows of A which are members of B.
You will need to transpose your matrices though.
Jan
Jan 2021년 1월 14일
I do not understand this sentence: "I want to know if the columns are completely unique - even if the same rows are filled in each they could have different values."
ismember(x,y,'rows') searches for equal rows in both matrices. This is exactly, what "if columns in one matrix are repeated elsewhere in the other matrix" means, isn't it?

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답변 (1개)

Adam Danz
Adam Danz 2021년 1월 13일
편집: Adam Danz 2021년 1월 13일
To determine if two arrays are 100% identical, use isequal or isequaln to ignore NaN values.
To determine if columns in matrix A are found in matrix B,
% create demo data
rng('default')
A = randi(3,3,20);
B = randi(4,3,20);
for i = 1:size(A,2)
isInB(i) = ismember(A(:,i)', B','rows');
end
isInB is a 1xn logical vector for n columns of A where isInB(i) indicates whether column i of A is found in B.
To find the column numbers in B that match each column number in A
isMatchInB = false(size(A,2),size(B,2));
for i = 1:size(A,2)
isMatchInB(i,:) = arrayfun(@(j)isequaln(A(:,i),B(:,j)),1:size(B,2));
end
isInB = any(isMatchInB,2);
isInB is a 1xn logical vector for n columns of A where isInB(i) indicates whether column i of A is found in B.
isMatchInB is an ixj logical vector where isMatchInB(i,j) indicates where colum i of A matches column j of B.
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Adam Danz
Adam Danz 2021년 1월 14일
You could try storing the subscript indicies instead,
c = cell(1,size(A,2));
for i = 1:size(A,2)
c{i} = find(arrayfun(@(j)isequaln(A(:,i),B(:,j)),1:size(B,2)));
end
Bruno Luong
Bruno Luong 2021년 1월 14일
편집: Bruno Luong 2021년 1월 14일
Or using sparse matrix
isMatchInB = sparse([],[],false(0),size(A,2),size(B,2));

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