Solving a matrix using MatLab?

I need help solving the following matrix
>> M = [1 0 2 1 18; 0 -3 -3 0 -8; -2 -3 0 0 -41; -1 0 -1 1 16]
I was able to get it to the following
>> M = [1 0 2 1 18; 0 1 1 0 2.6667; 0 2.3333 0 -.6667 5.2222; 0 0 1 2 34]
I'm stuck. Anybody willing to help me through this. Thanks in advance
It has to be reduced into RREF. What would my next step be?

답변 (2개)

Tobias
Tobias 2013년 4월 10일

0 개 추천

Do you have to do it manually? If you have MATLAB at your disposal, why not just use the rref-command?
rref(M)
^ That should fix your problem
Amed
Amed 2013년 4월 10일

0 개 추천

I have to do it manually and rref(M) at the end to show it's in RREF form

댓글 수: 7

Tobias
Tobias 2013년 4월 10일
편집: Tobias 2013년 4월 10일
Are you sure you have not made a mistake somewhere? I am not getting the same value as you have in your last step and going onwards from there, probably won't do you any good.
By the way: Use comment and not answer
Amed
Amed 2013년 4월 10일
Error as in what? I'm solving using matlab so i'm not too sure where I went wrong.. I'll start from the beginning and step by step what I do
Amed
Amed 2013년 4월 10일
편집: Amed 2013년 4월 10일
>> M = [1 0 2 1 18; 0 -3 -2 0 -8; -2 -3 0 0 -41; 1 0 -1 1 16];
>> M2=M;
>> M2(3,:) = M2(3,:)+(2*M2(1,:));
>> M2(4,:) = M2(4,:)-M2(1,:);
>> M3 = M2;
>> M3(3,:) = M3(3,:)+M3(2,:);
>> M3(3,:) = M3(3,:)-M3(2,:);
>> M3(3,:) = M3(3,:)-M3(2,:);
>> M3(2,:) = (-1/3)*M3(2,:)
end I end up with [1 0 2 1 18; 0 1 .6667 0 2.6667, 0 0 6 2 3, 0 0 -3 0 -2];
Amed
Amed 2013년 4월 10일
I'm so lost...
Amed
Amed 2013년 4월 10일
Anybody help, it's due like real soon. I'm stuck in the water on this one
Amed
Amed 2013년 4월 10일
hello, anybody out there?
Amed
Amed 2013년 4월 10일
yoyoyoyoyo

이 질문은 마감되었습니다.

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질문:

2013년 4월 10일

마감:

2021년 8월 20일

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