How to divide Vectors of different length?

I have declared vectors 'a' and 'b'

Now the I want divide vector 'a' by vector 'b' and the result must store it in vector 'c'

The problem is vectors 'a' and 'b' are different lengths

But I managed by using the code given below;

Any one can try to assist this code to rewrite in a general format

a=linspace(1,16,16);

b=linspace(1,4,4);

c1 = a(1:4)./b(1);

c2 = a(5:8)./b(2);

c3 = a(9:12)./b(3);

c4 = a(13:16)./b(4);

c=[c1 c2 c3 c4];

c=[1,2,3,4,2.5,3,3.5,4,3,3.33,3.66,4,3.25,3.50,3.75,4;]

[Yao Li]

Is the length of a always an integral multiple of the length of b? It's important because we must first find out how many parts a is divided to.

Answer 1

[Azzi Abdelmalek]

a=linspace(1,16,16);
b=linspace(1,4,4);
d=reshape(a,[],numel(b))
out=bsxfun(@rdivide,x,b)
c=out(:)'

[Yao Li]

x should be d ^_^

This works well only the length of a is an integral multiple of the length of b.

Answer 2

[Andrei Bobrov]

c = a./kron(b,[1 1 1 1]);