Hi,
I am using nested loop to generate a range of variables and solve an equation.
for x = 1:1:20
for y = 1:1:20
for z = 1:1:20
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
end
end
end
The combination of variables (x,y,z) do not always form the root of the equation. When no solution is found, the Matlab function throws an error and exits the loop. However, I want the loop to continue and proceed checking the rest of the variable combinations. Is there a way to flag this error and continue through the looping process?
Thanks,
Abinav

 채택된 답변

James Tursa
James Tursa 2020년 12월 29일

0 개 추천

Something like this:
try
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
catch
continue
end

댓글 수: 1

Abinav
Abinav 2020년 12월 29일
Thanks. It worked. I was stuck with this for days.

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추가 답변 (1개)

Walter Roberson
Walter Roberson 2020년 12월 29일

0 개 추천

If func() is creating an error then use try/catch around the call to func()

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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2020년 12월 29일

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2020년 12월 29일

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