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Skip instance of a loop with error

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Gekkouga
Gekkouga 29 Dec 2020
댓글: Gekkouga 29 Dec 2020
Hi,
I am using nested loop to generate a range of variables and solve an equation.
for x = 1:1:20
for y = 1:1:20
for z = 1:1:20
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
end
end
end
The combination of variables (x,y,z) do not always form the root of the equation. When no solution is found, the Matlab function throws an error and exits the loop. However, I want the loop to continue and proceed checking the rest of the variable combinations. Is there a way to flag this error and continue through the looping process?
Thanks,
Abinav

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채택된 답변

James Tursa
James Tursa 29 Dec 2020
Something like this:
try
fn = x+y+z; %The function is just a representation. I am actually performing a Finite Element Analaysis
ans = func(fn); %The equation is solved using an external function
catch
continue
end

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Gekkouga
Gekkouga 29 Dec 2020
Thanks. It worked. I was stuck with this for days.

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추가 답변(1개)

Walter Roberson
Walter Roberson 29 Dec 2020
If func() is creating an error then use try/catch around the call to func()

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Gekkouga
Gekkouga 29 Dec 2020
Thanks. try/catch worked.

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