Inverse matrix with for loop, dimensions are wrong I don't know how to fix it
이전 댓글 표시
C=[-2,3;
6,5]
[m,n]=size(C)
z=zeros(m,n)
%cofactor
c1= C(2,2)
c2 = -C(1,2)
c3 = -C(2,1)
c4 = C(1,1)
%cofactor matrix
c = [c1,c3;
c2,c4]
for i= 1:m
for j= 1:n
for k=1/det(C(i,j))
for h= transpose(c)
z(i,j)= k*h
end
end
end
end
댓글 수: 1
Jan
2020년 12월 24일
Before the readers can fix your code, they need to know, what you try to do. "Inverse matrix with foor loop" is not clear enough.
det(x) is x, if x is a scalar. So "for k=1/det(C(i,j))" is the same as "k = 1 / C(i,j)".
What is the purpose of "for h= transpose(c)"?
답변 (0개)
카테고리
도움말 센터 및 File Exchange에서 Logical에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!