Move multiple rows without swapping

Hello,

I have a mxn matrix of binary data. I want to write a code where I find the rows in column n which have 1s in them and move them to bottom of the row. I want a generalised code for this as it will be in a loop where multiple iterations of this will be executed.

%For example, assume this is my matrix
%    a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 0 0 1 0 1 1 0 1 0 1 0;  %2
     0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1;  %4
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 1 0 0 1 0 0 0 0 0 1 0]; %6

%In column 'l' there are 2 rows with 1s in them (row 3 and 4). 
% I want to move rows 3 and 4 to the bottom. My final matrix should look like this.

%    a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 0 0 1 0 1 1 0 1 0 1 0;  %2  
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 1 0 0 1 0 0 0 0 0 1 0;  %6
     0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1]; %4

%Any help is appreciated. I thank in advance.

Answer 1

[Ive J]

H = randi([0 1], 6, 10)
H =

     0     1     0     1     1     0     0     0     1     0
     1     1     1     0     1     1     0     1     1     1
     0     0     0     0     1     0     0     1     0     1
     1     1     0     0     1     1     1     0     0     1
     1     1     0     0     1     1     1     1     0     0
     1     0     1     1     1     1     1     0     1     1

col = 9;
H = [H(H(:, col) < 1, :); H(H(:, col) > 0, :)]

     0     0     0     0     1     0     0     1     0     1
     1     1     0     0     1     1     1     0     0     1
     1     1     0     0     1     1     1     1     0     0
     0     1     0     1     1     0     0     0     1     0
     1     1     1     0     1     1     0     1     1     1
     1     0     1     1     1     1     1     0     1     1

[Rishi Balasubramanian]

That works perfectly. Thank you.

[Rishi Balasubramanian]

Hey I have another question. How would I choose that over a range?

%    a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 0 0 1 0 1 1 0 1 0 1 0;  %2
     0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1;  %4
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 1 0 0 1 0 0 0 0 0 1 0]; %6

%For ex in my matrix if I only wanted to look at column 'k' over rows 1 to 5, how can I use that?
%I want my final matrix to be something like this.
%    a b c d e f g h i j k l
H = [0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1;  %4
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 1 0 0 1 0 0 0 0 0 1 0]; %6
     0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 0 0 1 0 1 1 0 1 0 1 0;  %2

[Ive J]

You can also do that with some tiny modifications

H =
     0     1     0     1     1     0     0     0     1     0
     1     1     1     0     1     1     0     1     1     1
     0     0     0     0     1     0     0     1     0     1
     1     1     0     0     1     1     1     0     0     1
     1     1     0     0     1     1     1     1     0     0
     1     0     1     1     1     1     1     0     1     1
col = 9;
rowsOnly = 1:5; % i.e. do not change row 6
idxRows = ismember(1:size(H, 1), rowsOnly)'; % ~idxRows: row 6
idx0 = H(:, col) < 1 & idxRows; % 3, 4 and 5
idx1 = H(:, col) > 0 & idxRows; % 1 and 2
H = [H(idx0, :); H(~idxRows, :); H(idx1, :)]
     0     0     0     0     1     0     0     1     0     1
     1     1     0     0     1     1     1     0     0     1
     1     1     0     0     1     1     1     1     0     0
     1     0     1     1     1     1     1     0     1     1
     0     1     0     1     1     0     0     0     1     0
     1     1     1     0     1     1     0     1     1     1

[Rishi Balasubramanian]

Wonderful, that works perfectly. Thanks man.

[Rishi Balasubramanian]

Hello, One more question. Hopefully its the last. Say I want to move a single row to a specific postion? How do I do that?

For ex

%    a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 0 0 1 0 1 1 0 1 0 1 0;  %2
     0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1;  %4
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 1 0 0 1 0 0 0 0 0 1 0]; %6

% I want to move row 2 to row index 5 such that my final matrix is -

%    a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0;  %1
     0 1 1 0 0 1 1 1 0 0 0 1;  %3
     0 1 1 0 1 0 1 0 1 0 0 1;  %4
     0 0 0 1 1 0 0 1 1 0 0 0;  %5
     0 0 0 1 0 1 1 0 1 0 1 0;  %2
     0 1 0 0 1 0 0 0 0 0 1 0]; %6