resolution of PDE

조회 수: 1 (최근 30일)
mouna
mouna 2011년 5월 7일
I have a system of equations:
(?C/?t)+(u/?)?C/?z+((1-?)/?)*(?s/?f)*Ki*a*(q-KéqC)=0
?q/?t=-Ki a(q-KéqC)
the initial condition is:
t=0, q=q0 and C=C0,z>0
the boundary conditions are:
z=0;C=0 and q=q0
z=L; ?C/?z=0 ,?q/?z=0
this is my program: i don't find the error so pleaaase help me. thanks in advance.
function modelediffusion
m=0;
z=linspace(0,1,26);
t=linspace(0,2,200);
sol = pdepe(m,@pdexpde,@pdexic,@pdexbc,z,t);
C = sol(:,:,1);
q = sol(:,:,2);
figure
plot(t,C(:,15))
function[g,f,s]= pdexpde(z,t,C,DCDz)
rhos=0.55;
rhof=0.385;
dp=0.03;
a=6/dp;
epsilon=0.45;
Ki=1.4E-7;
u=0.098;
Keq=16.86;
A=Ki*a*(C(2)-(Keq.*C(1)));
B=((1-epsilon)/epsilon)*(rhos/rhof)*A;
g=[1; 1];
f=[0; 0];
s=[((-u)/epsilon).*DCDz-B; A];
function C0 = pdexic(z)
c0=1.5E-3;
q0=2.53E-2;
C0 = [c0; q0];
% -------------------------------------------------------------------------
function [pl,ql,pr,qr] = pdexbc(zl,Cl,zr,Cr,t)
q0=2.53E-2;
pl = [C1(1);q0-Cl(2)];
ql = [1; 0];
pr = [0; 0];
qr = [0; 1];
  댓글 수: 5
Walter Roberson
Walter Roberson 2011년 5월 8일
The question marks indicate derivative. Except the ones that appear isolate right after a "/" -- I don't know what those are.
Is KéqC a complete variable, or is it Kéq * C ?
Walter Roberson
Walter Roberson 2011년 5월 8일
((1-?)/?) is a puzzler alright.

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답변 (1개)

Andrew Newell
Andrew Newell 2011년 5월 8일
Here is one error: in this line,
pl = [C1(1);q0-Cl(2)];
the first C1 is C followed by the numeral 1, but it should be C followed by the letter l.
Debugging note: It is a good idea to have just one command per line. That way, when you get an error message, you know which command triggered it (if not which command actually caused it).
  댓글 수: 1
mouna
mouna 2011년 5월 8일
thank you very much

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