Creating a growing list

for r = 1 : whatever
    for c = 1 : whatever2
        if Range > 50
            Joey  = {('Bi**h Changed'),r,c}

Hi,

I want joey to be a list, growing, currently it's overwriting at index one.

Quick fix please, I've seen long winded methods but I'm sure there's something very simple.

Example:

Joey = {Joey,('Bi**h Changed'),r,c} which is silly. Or having a counter, Joey {counter} = ect..... counter = counter +1, which is also silly.

Answer 1

[per isakson]

Add

Joey = cell(0);

before the loops and replace

Joey  = {('Bi**h Changed'),r,c}

by

Joey(end+1:end+3)  = {('Bi**h Changed'),r,c};

Silly or not is in the eyes of the beholder.

Or you might want

Joey{end+1}  = {('Bi**h Changed'),r,c};

[Saud Alfalasi]

Joey(end+1:end+3) = {('Bi**h Changed'),r,c};

Hey man this is the best I could get, it displayed a horizontal list however beggers cant be choosers.

Answer 2

[Image Analyst]

There are basically 2 ways that I know of and you listed them. I don't think they're silly. Using a counter is more efficient than appending (your first method). Using a table is even more efficient than a cell array. Even more efficient would be to allocate a large amount of empty cells - way more than you think you would need - then crop the array after the loop

Joey = cell(1000, 1)
counter = 1;
for r = 1 : whatever
    for c = 1 : whatever2
        if Range > 50
            Joey(counter)  = {('Bi**h Changed'),r,c}
            counter = counter + 1;
        end
    end
end
Joey = Joey(1:counter); % Crop to however many we actually ended up needing.

[Saud Alfalasi]

Hi Image Analyst, I want to show you what I've produced after picking your brain (repeadly). Can I send you a file?

(just to show you, nothing else)(I think and hope you'll be impressed)

Saud