How can I read file names and convert them to a matrix? I have more than one file and I want to read their contents in one loop of the program. Thanks

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Tobias
Tobias 2013년 4월 4일
What is your current code? I assume you must have tried something yourself. Which errors are you getting?
Jan
Jan 2013년 4월 4일
It is not useful to convert filenames to a matrix. Do you want to import the file's contents into a matrix?
John
John 2013년 4월 12일
no I need to read the contents of a specific folder's file names (as text), then run selection rule to pick names only that i want.
The problem is that files being send to a folder, with names of the format (yyyymmddhh.jpg) so each day there is a marked file as (yymmddT.jpg)... (T for terminate). The names are varying, i can't read all by fopen commands, i can't specify the required name unless they are in some form.

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Ahmed A. Selman
Ahmed A. Selman 2013년 4월 18일

0 개 추천

Download a function file called folderFiles.m.
It'll do the job for you, hopefully.

추가 답변 (2개)

ChristianW
ChristianW 2013년 4월 4일

0 개 추천

doc dir
D = dir([myfolder 'my*file*name*.*']);
files = {D.name}';

댓글 수: 2

how to use files? I used it like
D = dir(['C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down' '*.jpg'])
files = {D.name}';
files =
{}
any ideas?
Jan
Jan 2013년 4월 18일
편집: Jan 2013년 4월 18일
This means, that no file matchs the filter:
'C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down*.jpg'
Perhaps you want:
'C:\Documents and Settings\John\My Documents\MATLAB\Pic_Down\*.jpg'
Note: fullfile() is much better for constructing file names than STRCAT, HORZCAT or [.].

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Jan
Jan 2013년 4월 4일

0 개 추천

It is always a good idea to read the FAQ, because it is efficient to profit from the errors of others.

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