parfor indexing and order
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[a,b,c]=size(Mask); % a=b=c=3;
parfor i=1:size(Mask,3)
i
end
I was expecting to see i=1,i=2,i=3 in a sequence as one would see in a for loop but it is giving me i=3,i=2,i=1 . This is in reverse order. I cant figure out the reason.
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Edric Ellis
2013년 4월 4일
0 개 추천
PARFOR loops can run in parallel, and as such, the iterations might run in any order. You should not rely on this order. In particular, as you have observed, PARFOR starts running iterations in reverse order.
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도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
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