derive new variable with random float values using for loop

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Arturo Jr. Ongkeko
Arturo Jr. Ongkeko 2020년 12월 12일
댓글: Arturo Jr. Ongkeko 2020년 12월 13일
Hi, I am trying to derive a new variable with random float values using for loop. Tried using randn.
for i=1:length(hosp_yn_coded)
if (hosp_yn_coded(i)==1)
los_total(i)=randn([0 2],1,1) % must be float bet 0-2 e.g. 0.1,0.2,0.4,1.4,1.2
else
los_total(i)=randn([0 1],1,1) % must be float bet 0-2 e.g. 0.1,0.2,0.4,1.4,1.2
end
end
Thanks so much!

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Jeff Miller
Jeff Miller 2020년 12월 13일
Despite your comments, I guess you want 0-1 for the second option, not 0-2.
I guess you want all numbers in the range to be equally likely, so randn is not the right choice.
I wouldn't use a for loop here, but you can if you want:
for i=1:length(hosp_yn_coded)
if (hosp_yn_coded(i)==1)
los_total(i)=2*rand; % rand gives 0-1, so 2*rand is 0-2
else
los_total(i)=rand;
end
end
  댓글 수: 1
Arturo Jr. Ongkeko
Arturo Jr. Ongkeko 2020년 12월 13일
Hi, Jeff! Thanks so much. I am trying to be comfortable with for-loops so this is like a practice for me.

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