Displaying a linked list as an array?

How would I display a linked list as an array of the values of every node in the list, in the order of which the list traverses? Ok, so let's say I have list structure with list.root as the index of the first node in the list. Each node has a value and a next pointer, indicating the index of the next node in the list. How would I show every value within the list structure as a single array of values?

[Jan]

There is a nearly infinite number of methods you could implement a linked list in Matlab. So how could we know the structure of your data? Please add any details by editing the question - not as answer or comment.

Answer 1

[Walter Roberson]

Start an array with []. Start at list.root . Repeat {If the current list point is not the end of list, add list.value to the end of the array, and make list.next the current list point.}

[Joe]

So would I use a while loop as the current list point not equal to the end of the list as the condition?

[Walter Roberson]

end-of-list marker rather than the last node, because you need to include the information from the last node.

[Joe]

Okay I think I have it down, thank you for the help, very much appreciated!