Extract sequences from vector
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Dear Forum members,
I have a question I could not find any solution for. I have a vector, let's say
U=[2,2,5,7,3,4,4,4,2,2,2,3].
I also have a sequence, which is
s=[2,2,3].
I now want to find all the indexes in U, where my sequence s could be built from. In my case, that would be
(1,2,5), (9,10,12), (10,11,12), (9,11,12). So the problem is the sequences have to be build first from U and do not exist as in s. I find this quite tough and would be happy if someone had a solution.
I have Matlab 7.13.
Thanks a lot! Peter
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Azzi Abdelmalek
2013년 2월 27일
편집: Azzi Abdelmalek
2013년 2월 27일
Are you looking for all the sequences?, for example (2,5,7,3)
답변 (4개)
Babak
2013년 2월 27일
perms
nchoosek
might be helpful in finding combinations of the elements of different size vectors.
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Saeid Abrari
2020년 10월 6일
for dig=1:16
ndata = length(Frame);
ndata_1=length(digit(dig,:));
n_diff=abs(ndata-ndata_1);
Sound_1=[digit(dig,:)';zeros(n_diff,1)];
sx = sum(Frame.^2);
sy = sum(Sound_1.^2);
maxlag = ndata-1;
cnt = 0;
for lag = -maxlag:maxlag
cnt = cnt + 1;
sxy = 0;
for i=1:ndata
j = i + lag;
if j>0 && j<=ndata
sxy = sxy + Frame(i) * SoundVec_1(j);
end
end
cc(cnt) = sxy / sqrt(sx*sy); % correlation coefficient
ck(cnt) = sxy; % cross-correlation value
lags(cnt) = lag;
end
simil(dig)=max(cc);
[~,i] = max(cc);
Ts=1/Fs;
t1=Ts:Ts:FrameLen*Ts;
norm_ck=cc/max(cc);
lx = (length(norm_ck));
half = ceil(lx/2);
norm_ck_p=norm_ck(1:half);
td = i - ndata;
tau1=lags/Fs;
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Saeid Abrari
2020년 10월 6일
for dig=1:12
ndata = length(Frame);
ndata_1=length(digit(dig,:));
n_diff=abs(ndata-ndata_1);
Sound_1=[digit(dig,:)';zeros(n_diff,1)];
sx = sum(Frame.^2);
sy = sum(Sound_1.^2);
maxlag = ndata-1;
cnt = 0;
for lag = -maxlag:maxlag
cnt = cnt + 1;
sxy = 0;
for i=1:ndata
j = i + lag;
if j>0 && j<=ndata
sxy = sxy + Frame(i) * SoundVec_1(j);
end
end
cc(cnt) = sxy / sqrt(sx*sy); % correlation coefficient
ck(cnt) = sxy; % cross-correlation value
lags(cnt) = lag;
end
simil(dig)=max(cc);
[~,i] = max(cc);
Ts=1/Fs;
t1=Ts:Ts:FrameLen*Ts;
norm_ck=cc/max(cc);
lx = (length(norm_ck));
half = ceil(lx/2);
norm_ck_p=norm_ck(1:half);
td = i - ndata;
tau1=lags/Fs;
%Find the maximum corellation index(digit)
if(max(simil)>0.5)
[seqm sequ(s_loc)]=max(simil);
s_loc=s_loc+1;
end
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