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Extract columns from matrix based on a vectors values

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Tom Hagéus
Tom Hagéus 2020년 11월 6일
댓글: Jon 2020년 11월 6일
I want to extract the columns of a matrix A (mxn), based on a vector B's values into a new matrix C, meaning:
Which also should be dependent on B's dimensions (1xm):
For example:
Then C should be:
I want this to work for any dimensions of n and m.
I have tried:
but it doesn't work for B=[3,1] since it takes column by column.

채택된 답변

Jon 2020년 11월 6일
편집: Jon 2020년 11월 6일
I think this should do it for you:
C = A(:,B)
  댓글 수: 2
Jon 2020년 11월 6일
Glad this works for you. Please accept this answer so others with a similar issue will know an answer is available.

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추가 답변(1개)

dpb 2020년 11월 6일
편집: dpb 2020년 11월 6일
>> A=[1,1,1,0;
>> A(:,B)
ans =
1 0
0 1
>> B=[3,1];
>> A(:,B)
ans =
1 1
0 2
meets the description of the vector B.
If you mean for B to be all columns from B(1):B(2) inclusive, then you have to be more explicit in how you write the expression:
>> A(:,B(1):sign(diff(B)):B(2))
ans =
1 1 1
0 1 2
This will require that B always be a 2-vector and B(1)~=B(2).

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