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Why are my PCA eigenvalues (Latent) are completely off?

조회 수: 13 (최근 30일)
Iza Korsmit
Iza Korsmit 2020년 10월 28일
편집: Sreeranj Jayadevan 2020년 11월 20일
I am trying to determine dimensionality based on eigenvalues (along with other criteria), but the eigenvalues I get from the pca function seem completely off. They are either very small (all below 1) or very big, and do not average to ~1. When I run the PCA on the same data in SPSS, my eigenvalues do seem normal.
Am I running the analysis incorrectly, or should I interpret the eigenvalues that Matlab gives differently?
My data is a matrix of 16 variables (columns) and 61 observations (rows). I have rescaled the data so that each column has a range of 0-1, since the variables in the raw data have wildely different ranges. When I run the rescaled matrix, I get all eigenvalues below 1. With my raw data matrix, eigenvalues have a really big range from ~500 to below 1.
Attached is a csv of my raw data matrix.
I ran the pca as follows:
[COEFF, SCORE, LATENT, TSQUARED, EXPLAINED] = pca(matrix);
I looked at LATENT for the eigenvalues.
I also tried different variations and specifications of the function, which made no difference for the eigenvalues, such as:
[COEFF, SCORE, LATENT, TSQUARED, EXPLAINED] = pca(matrix,'algorithm', 'eig')
%or
[COEFF, SCORE, LATENT, TSQUARED, EXPLAINED] = pca(matrix,'algorithm', 'eig','Centered',false)
%or
[COEFF, SCORE, LATENT, TSQUARED, EXPLAINED] = pca(matrix,'algorithm', 'eig','Centered',false,'Rows','all')
Though I'm pretty sure my rescaling is correct, since it did not give me any problems in SPSS, here is the code:
norm_matrix = raw_matrix;
minx = zeros(1,16);
maxx = zeros(1,16);
for i = 1:16
minx(i) = min(raw_matrix(:,i));
maxx(i) = max(raw_matrix(:,i));
norm_matrix(:,i) = (raw_matrix(:,i)-minx(i))/(maxx(i)-minx(i));
end
Here is an example of my LATENT output:
raw_LATENT =
1.0e+05 *
3.2033
1.4096
0.3762
0.1009
0.0466
0.0223
0.0064
0.0009
0.0002
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
0.0000
%or
norm_LATENT =
0.4348
0.2526
0.1842
0.0833
0.0702
0.0575
0.0439
0.0380
0.0281
0.0235
0.0154
0.0121
0.0098
0.0074
0.0050
0.0044
0.0034
0.0022
0.0018
0.0013
0.0011
0.0002
0.0000
0

채택된 답변

Sreeranj Jayadevan
Sreeranj Jayadevan 2020년 11월 17일
편집: Sreeranj Jayadevan 2020년 11월 20일
The eigenvalues you get after using pca() before rescaling the data is expected to behave in this manner. If you wish to choose the components with highest variances, then you can rescale the eigenvalues. For example, if you have a set of eigenvalues [900,50,25,15,2,2,2,2,0.001,0.0005,0.00001.......], then after rescaling to a range [0,1] (so that you can easily select the components with highest variances), the values will become [0.9,0.05,0.025,0.002.....]. I have not used SPSS for statistical analysis and hence I am not aware of what SPSS outputs as the results.
Check if the parameter 'EXPLAINED' returns the required results. It outputs the percent variability explained by the principal components.
Data standardizing is done before using pca() to eliminate the influence of one feature over another. The normalization method to be followed depends on your data. But in case the features contain outliers, then you may have to normalize the data using a different approach (please refer to normalize() function in MATLAB: https://in.mathworks.com/help/matlab/ref/double.normalize.html), before using pca().
  댓글 수: 1
Iza Korsmit
Iza Korsmit 2020년 11월 20일
Thank you!
You are right, the problem had to do with rescaling! I had simply 'normalized' all my columns to a 0-1 range, thinking that was sufficient. Now I used the normalize() function to rescale, and the eigenvalues make more sense, and are identical to what SPSS and R provide as output.

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