n(x)
조회 수: 15 (최근 30일)
이전 댓글 표시
can someboduy tell me wqhat is does these three kind of code mean? I mean why code3 is not working and what dows a( r ) actually mean? hwo does these change the layout? by rthe way this is not a homework but only my own thought :)
CODE1)
a=[0 1];
for r=3:100
a(r)=(r-1)+(r-2);
end
disp(a)
CODE2)
a=[0 1];
for r=3:100
a(r)=a(r-1)+a(r-2);
end
disp(a)
CODE3)
a=[0 1];
for r=3:100
a(r)=a(r-1)+a(r-2);
end
disp(a)
댓글 수: 2
채택된 답변
drummer
2020년 10월 25일
편집: drummer
2020년 10월 25일
CODE1)
a=[0 1]; % you tell MATLAB a is a vector
for r=3:100 % the for loop you understand, right?
a(r)=(r-1)+(r-2); % you're attributing to the rth term of your vector a values of (r - 1) + (r - 2)
% the 1st iteration will be a(3) = (3 - 1) + (3 - 2); a(4) = (4 - 1) + (4 - 2); so on...
end
disp(a)
CODE2)
a=[0 1]; %from this line, a(1) = 0 and a(2) = 1.
for r=3:100
a(r)=a(r-1)+a(r-2); % the difference between this and code 1) is that you're performing
% the summation calling the indexes in the vector a, rather than r values.
% so a(3) = a(2) + a(1) = 0 + 1 = 1
% In code 1, a(3) = 2 + 1 = 3
end
disp(a)
Code 3) is the same as 2) Walter mentioned.
Hope that helps...
Cheers
추가 답변 (0개)
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!