WHILE loop with a condition on a vector and Scalar

PacksA=zeros(1,10);
j=1;
n=1;
B=10
while PacksA(n,n:j)<B
    i=i+1;
    j=j+1;
    if j>10
        break
    end
    #instruction
end
n=n+1
PacksA(1:n,1:j)=PacksA

basically.

First itinerary of the while

Compare the first element of the matrix PacksA(1,1) with B.

if true, execute instructions inside the while

update the value of PacksA

if false, exit the while and increment n, and the value of PacksA(1,1) is updated in PacksA

Again compares the value of PacksA(1,1) updated with B and others the value PacksA(1,2) with B

if they are true, execute statements inside the while

update the values of PacksA that meets

if they are false, exit the while and increase n and the value of PacksA(1,1) or/and PacksA(1,2) is updated in PacksA

Again compares the value of PacksA(1,1) updated with B and others the value PacksA(1,2) updated with B, and others the value PacksA(1,3) with B

if they are true, execute statements inside the while

update the values of PacksA that meets

if they are false, exit the while and increase n and the value of PacksA(1,1) or/and PacksA(1,2) or/and PacksA(1,3) is updated in PacksA

when the values PacksA are updated, it is not compared any more and the process continues up to 10.

[Konstantin]

Are you speaking about something like this?

while all( PacksA(n,n:j) ) < B ) % all elements must be smaller than B

or

while any( PacksA(n,n:j) <B ) % any of lements must be smaller then B

[Fidele Adanvo]

I say the following:

while all PacksA=zeros(1,10)<B and all the values of PacksA updated in #code

exemple

PacksA=[0 0 0 0]

j=1;

B=10

while PacksA(1,j)<B

j=j+1;

if j>4

break

end

#instruction

PacksA(1,j)=PacksA(1,j)+2 % re-compare this updated value of A together with the next value of vector PacksA. exemple While PacksA(1,1)<B (updated) && PacksA(1,2)<B (next value of PacksA )

in another word in each comparison enter a next new value of the vector PacksA together with the values of PacksA(1,j) were updated and have not left the loop.

end