MATLAB initial velocity graph

I have completed the first dot point as follows:

disp ('Initial Velocity')

disp ('Displacement Input')

prompt1= 'Initial displacement (metres): ';

s0 = input(prompt1); %s0=10 metres

prompt2= 'Final displacement (metres): ';

s = input(prompt2); %s=10 metres

prompt3= 'Final time (seconds): ';

t = input(prompt3); %0.8 seconds

v0 = ((s-s0)+(1/2).*(981/100).*t.^2)/t; %initial velocity equation

disp ('Result:')

disp ('Initial Velocity: ')

disp (v0)

However I am stuck on doing the second point, this is my code so far:

s0=10;

s=10;

t = 0.5:0.1:1.5;

v0 = ((s-s0)+(1/2).*(981/100).*t.^2)/t;

plot (v0, t)

Any help is greatly appreciated thank you!!

Answer 1

[Gaurav Chaudhary]

Hello,

I understand the issue you are facing where the velocity is not a 1D array. To make velcoity a 1D array please use the dot(.) operator.

For Example:

for the following statement the output is a double datatype

>>v0 = ((s-s0)+(1/2).*(981/100).*t.^2)/t;

V0 can be changed to a 1D array using the following command using dot operator

>>v0 = ((s-s0)+(1/2).*(981/100).*t.^2)/.t;

This should solve the issue you are facing.