How to plot a function like this in matlab
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p=0.5*(1-x^2)/((1+(x^2)-2*x*cos(t))^(3/2))
here t varies from -pi to pi x is a constant like for example 0.1
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Jan
2013년 2월 1일
What about:
x = 0.1;
t = linspace(-pi, pi, 200);
p = 0.5 * (1 - x.^2) ./ ((1 + x.^2 - 2 .* x .* cos(t)).^(3/2));
plot(t, p);
Such methdos are explained exhaustively in the Getting Started chapters of the documentation and help plot offer detailed information also.
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Wayne King
2013년 2월 1일
x = 0.1;
t = -pi:.01:pi;
p=0.5*(1-x^2)./((1+(x^2)-2*x*cos(t)).^(3/2));
plot(t,p)
I'm guessing you really mean plot p as a function of t
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