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error bvp4c a single jacobian encountered

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federico midei
federico midei 2020년 10월 7일
Hi, I'm trying to plot the P value (corresponding to a peak in a P-umax plot) in function of "s", a variable linspaced between 0.1 and 2.
I've tried to write something like this but I don't know what to put in the Pcr findpeak function and I'm obtaining an error for the bvp4c.
I've tried to write this code:
clc;
clear;
clear;
%------------------------------------------------------------------------
ni=0.3;
L=50;
R=20;
E=210000;
E1=E/(1-ni^2);
%-----------------------------------------------------------------------
s= linspace(0.1,2,10);
I = zeros(size(s));
k = zeros(size(s));
Pcr = zeros(size(s));
%%
P=linspace(7800,3300000,10);
y_max_values= zeros(size(P));
for i=1:length(s)
for j=1:length(P)
f = @(z,u) [u(2); u(3); u(4); (-1/(E1*I(i)))*((P(j)*u(3))+(k(i)*u(1)))];
bc = @(ua, ub) [ua(1); ua(2)-0.00000001; ub(1); ub(2)+0.00000001];
zmesh = linspace(0, L, 100000);
iguess= @(z) [0; 0; 0; 0];
solinit = bvpinit(zmesh, iguess);
Sol= bvp4c(f, bc, solinit);
x = Sol.x;
y = Sol.y;
idx = (x > 50) & (x < 180);
x_new = x(idx);
y_new = y(1, idx);
y_max_values(j) = max(y_new);
Pcr=findpeak (?) %what I should put here?
end
end
%%
figure
hold on
grid on
plot(s, Pcr)
xlabel ('s [mm]')
ylabel ('Pcr [N]')
I'm obtaining this error:
Error using bvp4c (line 251)
Unable to solve the collocation equations -- a singular Jacobian encountered.
Error in plot_s_Pcr (line 33)
Sol= bvp4c(f, bc, solinit);
I've written a code that plots P-umax for s=1 but I need it to be repeated for every s value
clc;
clear;
close all;
R=20;
L=3*75;
s=1;
ni=0.3;
E=210000;
w=2;
K=0.5;
%
E1=E/(1-(ni^2));
I=(2*pi*R*(s^3))/12;
k=2*pi*((E*s)/R);
P = linspace(400000,9000000);
y_max_values = zeros(size(P));
for i=1:length(P)
f = @(z,u) [u(2); u(3); u(4); (-1/(E1*I))*((P(i)*u(3))+(k*u(1)))];
bc = @(ua, ub) [ua(1); ua(2)-0.00000001; ub(1); ub(2)+0.00000001];
zmesh = linspace(0, L, 100000);
iguess= @(z) [0; 0; 0; 0];
solinit = bvpinit(zmesh, iguess);
Sol= bvp4c(f, bc, solinit);
x = Sol.x;
y = Sol.y;
idx = (x > 50) & (x < 180);
x_new = x(idx);
y_new = y(1, idx);
y_max_values(i) = max(y_new);
end
figure
hold on
grid on
plot(y_max_values, P)
legend ('cilindro 1 w0')
xlabel ('u_max [mm]')
ylabel ('P [N]')
So I need to find in the plot, the P value corresponding to the first peak of the following P-umax plot, where the umax value moves from zero in the first time. (8x10^5 in this case), and repeat this procedure for every "s".
The P value corresponding to peak I'm trying to find has to be assigned to "Pcr"
Could someone help me out ?
Is the the code structure right for the aim I need to?

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