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Too Many Output Arguments

조회 수: 7 (최근 30일)
Tyler Reohr
Tyler Reohr 2020년 10월 6일
댓글: Walter Roberson 2020년 10월 7일
I'm using Matlab to solve for the constrained optimization of f(x,y,z) = 6x+6y+5z with a constraint of 3x^2+3y^2+5z^2 = 29.
My code looks like this:
clc
syms x y z t l
f = 6*x + 6*y +5*z
c = 3*x^2+3*y^2+5*z^2
c1 = 29
gFunc = gradient(f)
gConst = gradient(c)
eqn1 = gFunc(1,1) == l * gConst(1,1)
eqn2 = gFunc(2,1) == l * gConst(2,1)
eqn3 = gFunc(3,1) == l * gConst(3,1)
eqn4 = c == c1
[xsoln,ysoln,zsoln,lsoln] = solve([eqn1,eqn2,eqn3,eqn4],[x,y,z,l])
When I run the code, I get an error in saying that [xsoln,ysoln,zsoln,lsoln] = ... has too many output arguments, but I am solving 4 equations for 4 variables, and want 4 outputs, so I don't see how I am getting this error.
Any tips? Thanks!

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Walter Roberson
Walter Roberson 2020년 10월 7일
clc
syms x y z t l
f = 6*x + 6*y +5*z
f = 
6x+6y+5z
c = 3*x^2+3*y^2+5*z^2
c = 
3x2+3y2+5z2
c1 = 29
c1 = 29
gFunc = gradient(f)
gFunc = 
665
gConst = gradient(c)
gConst = 
6x6y10z
eqn1 = gFunc(1,1) == l * gConst(1,1)
eqn1 = 
6=6lx
eqn2 = gFunc(2,1) == l * gConst(2,1)
eqn2 = 
6=6ly
eqn3 = gFunc(3,1) == l * gConst(3,1)
eqn3 = 
5=10lz
eqn4 = c == c1
eqn4 = 
3x2+3y2+5z2=29
[xsoln,ysoln,zsoln,lsoln] = solve([eqn1,eqn2,eqn3,eqn4],[x,y,z,l])
xsoln = 
(22)
ysoln = 
(22)
zsoln = 
(11)
lsoln = 
1212
Works for me in R2020a and R2020b . Which release are you using?
  댓글 수: 7
Tyler Reohr
Tyler Reohr 2020년 10월 7일
I couldn't get it to work so I reinstalled it to clear the cache or any settings I might have arbitrarily changed on accident. It worked after that so I don't believe it was a problem with the code. Don't know exactly what went wrong, but it's working now. Thanks!
Walter Roberson
Walter Roberson 2020년 10월 7일
You had accidentally assigned a value to a variable named solve

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