How to find all possible paths from point A to B in any direction in a matrix?

조회 수: 22 (최근 30일)
I have a MXN matrix and I select two given points A and B. How do I find and store all the possible unique paths form A to B? There are no constraint on which direction I can go from the current point, it can be up, down, left, right, or diagonal (in all four directions).
  댓글 수: 14
Walter Roberson
Walter Roberson 2020년 9월 27일
MATLAB permits recursive functions, using the same syntax as most other programming languages -- which is to say that you just place a call to the function you are in the middle of defining.
The limitation on recursion in MATLAB is that by default only 500 levels of recursion are permitted. However, you can change that by using
set(0,'Rec​ursionLimi​t',N)
where N is your new depth limit. Be warned that if you do this, then there is a risk of crashing the computation by running out of stack space, as each call takes up memory (a copy of all local variables must be saved.)
John D'Errico
John D'Errico 2020년 9월 29일
The important point to reconize is just the sheer enormity of the number of all possilbe paths, even for a small matrix.
Almost always there are better ways to solve a problem than a complete sampling of the space you wish to investigate. This is why optimization methods exist, to help you to avoid brute force sampling schemes.

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채택된 답변

Bruno Luong
Bruno Luong 2020년 9월 29일
편집: Bruno Luong 2020년 11월 20일
Tiny matrix of size 4 x 3.
All paths of two opposite corners:
  • 38 paths for 4-connectivity,
  • 2922 paths for 8-connectivity
clear
close all
m=4; n=3;
% Adjacent matrix of a graph of 4-connected grid of size m x n
[X,Y] = meshgrid(1:n,1:m);
mxn = numel(X);
I = sub2ind(size(X),Y(1:end-1,:),X(1:end-1,:));
J = I+1;
A = sparse(I,J,1,mxn,mxn);
I = sub2ind(size(X),Y(:,1:end-1),X(:,1:end-1));
J = I+size(X,1);
A = A + sparse(I,J,1,mxn,mxn);
A4 = A + A';
% Adjacent matrix of a graph of 8-connected grid of size m x n
I = sub2ind(size(X),Y(1:end-1,1:end-1),X(1:end-1,1:end-1));
J = I+size(X,1)+1;
A = A + sparse(I,J,1,mxn,mxn);
I = sub2ind(size(X),Y(2:end,1:end-1),X(2:end,1:end-1));
J = I+size(X,1)-1;
A = A + sparse(I,J,1,mxn,mxn);
A8 = A + A';
% source and destination
is = 1; js = 1;
id = m; jd = n;
s = sub2ind([m,n],is,js);
d = sub2ind([m,n],id,jd);
allp4 = AllPath(A4, s, d);
PlotandAnimation(4, A4, allp4, [m,n]);
allp8 = AllPath(A8, s, d);
PlotandAnimation(8, A8, allp8, [m,n]);
%%
function PlotandAnimation(nc, A, allp, sz)
fprintf('%d-connected %d x %d\n', nc, sz);
% Plot and animation
figure
[i,j] = ind2sub(sz,1:prod(sz));
nodenames = arrayfun(@(i,j) sprintf('(%d,%d)', i, j), i, j, 'unif', 0);
G = graph(A);
h = plot(G);
labelnode(h, 1:prod(sz), nodenames)
th = title('');
colormap([0.6; 0]*[1 1 1]);
E = table2array(G.Edges);
E = sort(E(:,1:2),2);
np = length(allp);
for k=1:np
pk = allp{k};
pkstr = nodenames(pk);
s = sprintf('%s -> ',pkstr{:});
s(end-3:end) = [];
fprintf('%s\n', s);
Ek = sort([pk(1:end-1); pk(2:end)],1)';
b = ismember(E, Ek, 'rows');
set(h, 'EdgeCData', b, 'LineWidth', 0.5+1.5*b);
set(th, 'String', sprintf('%d-connected, path %d/%d', nc, k, np));
pause(0.1);
end
end
%%
% EDIT: better code available in the comment
function p = AllPath(A, s, t)
% Find all paths from node #s to node #t
% INPUTS:
% A is (n x n) symmetric ajadcent matrix
% s, t are node number, in (1:n)
% OUTPUT
% p is M x 1 cell array, each contains array of
% nodes of the path, (it starts with s ends with t)
% nodes are visited at most once.
if s == t
p = {s};
return
end
p = {};
As = A(:,s)';
As(s) = 0;
neig = find(As);
if isempty(neig)
return
end
A(:,s) = [];
A(s,:) = [];
neig = neig-(neig>=s);
t = t-(t>=s);
for n=neig
p = [p; AllPath(A,n,t)]; %#ok
end
p = cellfun(@(a) [s, a+(a>=s)], p, 'unif', 0);
end %AllPath
  댓글 수: 4
Walter Roberson
Walter Roberson 2021년 9월 18일
Jagan, read about:
  • breadth-first search (bfs() in MATLAB)
  • A* algorithm (less common)
  • Dijkstra's algorithm (very common approach)
If what you need is the "cost" of the shortest path and not the particular edges, then there is an algorithm involving matrix multiplication.

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추가 답변 (1개)

Stijn Haenen
Stijn Haenen 2020년 9월 29일
With this script you got all possible paths, but it is very slow so you have to optimize it (shouldnt be that hard but dont have time for it anymore).
The script tries every path by going in any of the 8 directions at every step until it reaches its goal position.
clear
a=[1 2 3; 4 5 6];
start1=1;
start2=1;
goal1=2;
goal2=2;
abackup=a;
data=[];
for i=10^(numel(a)-1):10^numel(a)-1
pos1=start1;
pos2=start2;
route_i=num2str(a(pos1,pos2));
j=num2str(i);
abackup=a;
abackup(pos1,pos2)=NaN;
for n=1:numel(j)
if j(n)=='1'
try
if ~isnan(abackup(pos1-1,pos2))
pos1=pos1-1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='2'
try
if ~isnan(abackup(pos1-1,pos2+1))
pos1=pos1-1;
pos2=pos2+1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='3'
try
if ~isnan(abackup(pos1,pos2+1))
pos2=pos2+1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='4'
try
if ~isnan(abackup(pos1+1,pos2+1))
pos1=pos1+1;
pos2=pos2+1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='5'
try
if ~isnan(abackup(pos1+1,pos2))
pos1=pos1+1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='6'
try
if ~isnan(abackup(pos1+1,pos2-1))
pos1=pos1+1;
pos2=pos2-1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='7'
try
if ~isnan(abackup(pos1,pos2-1))
pos2=pos2-1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
if j(n)=='8'
try
if ~isnan(abackup(pos1-1,pos2-1))
pos1=pos1-1;
pos2=pos2-1;
route_i=sprintf('%s%g',route_i,a(pos1,pos2));
abackup(pos1,pos2)=NaN;
if pos1==goal1 && pos2==goal2
data(end+1)=str2num(route_i);break
end
end
catch
end
end
end
end
unique(data)

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