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Creating an array within a for loop

조회 수: 6 (최근 30일)
Timothy Russell
Timothy Russell 2013년 1월 27일
I have a plotting function which gets the points to plot from a for loop, i.e.
for i=1:length(rat2ind)
ind = A(:,1)==A(rat2ind(i),1); % pick all the rat locs for rat i
plot(A(ind,2),A(ind,3),randcolor);axis([-0.5 7.5, -0.5 7.5]) % plot rat i trajectory
hold on;
end
but instead of plotting the points, I'd like to save the points in an (n,2) array. I tried this:
for i=1:length(rat2ind)
ind = A(:,1)==A(rat2ind(i),1);
H=vertcat(H,[A(ind,1),A(ind,2),A(ind,3)]);
end
but it gave me a variable which is definitely not what I needed as its twice as large as my original data (the data, and my actual goal isn't really relevant here)
Thanks for any help
  댓글 수: 4
Cedric
Cedric 2013년 1월 27일
This line is suspicious to me:
ind = A(:,1)==A(rat2ind(i),1);
are you sure that it is not:
ind = A(:,1) == rat2ind(i) ;
Timothy Russell
Timothy Russell 2013년 1월 28일
changing this gives me exactly the same wrong answer...!

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채택된 답변

Timothy Russell
Timothy Russell 2013년 1월 28일
Thanks for the help, turns out that this function is exactly what I wanted:

추가 답변 (1개)

Matt J
Matt J 2013년 1월 27일
편집: Matt J 2013년 1월 27일
N=size(A,1);
map=double(bsxfun(@eq,sparse(A(:,1)),A(ratind,1).'));
ind=nonzeros( bsxfun(@times, (1:N).', map ) );
H=A(ind,1:3);
  댓글 수: 3
Matt J
Matt J 2013년 1월 29일
편집: Matt J 2013년 1월 29일
Yeah, I see that now. My guess is that it's because, as Cedric pointed out, you probably really want to be comparing with ratind instead of A(ratind,1).
Timothy Russell
Timothy Russell 2013년 2월 2일
Yeah you're right, sorry. The confusion came from trying to use exactly the same method in my plotting function, and forgetting what the variables actually represented. Thanks alot for the help, i'm actually starting to enjoy using matlab!_

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