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Error using vertcat Dimensions of arrays being concatenated are not consistent.

조회 수: 4 (최근 30일)
Jerico Yabut
Jerico Yabut 2020년 9월 16일
답변: VBBV 2021년 12월 9일
matrix1 = input("matrix 1 is \n");
matrix2 = input("matrix 2 is \n");
[M, N] = size(matrix1);
[P, Q] = size(matrix2');
if N == P
X = matrix1*matrix2
disp(X)
else
fprintf("Matrix multiplication can't be done.")
end
This is my code and we are tasked to do simple multiplication of matrices. This works fine in 2x2 or 1x1 or even 16x16 matrices but when it comes to 1x3 or 3x4 or 5x7, it doesnt work anymore. Thank you for answering
  댓글 수: 2
KSSV
KSSV 2020년 9월 16일
What is c, d, I, J? Variables are not defined, how do you expect us to help you?
Jerico Yabut
Jerico Yabut 2020년 9월 16일
Thanks for pointing that out. I already edited it.

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답변 (2개)

David Hill
David Hill 2020년 9월 16일
matrix1 = input("matrix 1 is \n");
matrix2 = input("matrix 2 is \n");
[M, N] = size(matrix1);
[P, Q] = size(matrix2);
if N == P
X = matrix1*matrix2;
disp(X)
else
fprintf("Matrix multiplication can't be done.")
end
  댓글 수: 1
Jerico Yabut
Jerico Yabut 2020년 9월 16일
I tried this however it doesn't work at 1x3 or 4x1 or 5x7. It only works on let's just say 4x4 or 2x2 or 10x10.it says that "Error using vertcat Dimensions of arrays being concatenated are not consistent."

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VBBV
VBBV 2021년 12월 9일
matrix1 = rand(1,3)%input("matrix 1 is \n"); This is example of 1 x3 matrix
matrix1 = 1×3
0.7567 0.2314 0.3456
matrix2 = rand(3,3)%input("matrix 2 is \n");
matrix2 = 3×3
0.2531 0.3500 0.0379 0.0466 0.7056 0.3046 0.0829 0.0319 0.9818
[M, N] = size(matrix1);
[P, Q] = size(matrix2);
if N == P
disp('The product is ')
X = matrix1.*matrix2
else
fprintf("Matrix multiplication can't be done.")
end
The product is
X = 3×3
0.1915 0.0810 0.0131 0.0353 0.1633 0.1053 0.0627 0.0074 0.3393

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