Replacing several values in multidimensional array simultaneously

조회 수: 4 (최근 30일)
I have a multidimensional array, e.g.
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
I want to replace several of the values in this array with the same value simultaneously. Specifically I want to do this column-wise, the result should be e.g.
A(:,2,1) = [-1 ; -2];
A(:,3,2) = [-1 ; -2];
yielding
A(:,:,1) = [1 -1 3 ; 4 5 -1];
A(:,:,2) = [7 -2 9 ; 10 11 -2];
I attempted this by
B = [2 3]; C = [1 2];
A(:,B,C) = [-1 ; -2];
but it does not give the wanted result.
Any idea on how to do this without performing a for-loop?

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Bruno Luong
Bruno Luong 2020년 9월 14일
편집: Bruno Luong 2020년 9월 14일
A(:,:,1) = [1 2 3 ; 4 5 6];
A(:,:,2) = [7 8 9 ; 10 11 12];
s = size(A);
A(:, sub2ind(s(2:3),[2 3],[1 2])) = 0 % = [0 0; 0 0]
  댓글 수: 2
David Hoffmeyer
David Hoffmeyer 2020년 9월 14일
편집: David Hoffmeyer 2020년 9월 14일
Thanks for your input. However, I have not been precise enough in my question. I need to replace a number of columns in the array with a column containing non-identical values (see the edited question), and not just 0. In that case your proposal does not work. Can you alter it correspondingly?
Bruno Luong
Bruno Luong 2020년 9월 14일
편집: Bruno Luong 2020년 9월 14일
Just replace the RHS as I hint in my answer with "% = [0 0; 0 0]"
A(:, sub2ind(s(2:3),[2 3],[1 2])) = [[-1;-2], [-1;-2]]

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