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Mean value of a subarray

조회 수: 8(최근 30일)
EldaEbrithil
EldaEbrithil 22 Aug 2020
댓글: EldaEbrithil 22 Aug 2020
Hi all
i have an array V=1x115 i want to create another array which contains the mean value neatly of the first 8 V values than of the subsequent 8 and so on... in pratical terms: mean(V(1:8)), mean(V(8:16)),...mean(V(112:end))
Thank you for the help
Regards
  댓글 수: 2
EldaEbrithil
EldaEbrithil 22 Aug 2020
Thank you Adam
I solved the problem thanks to your upper link, now i understand the logic for the moving average
Regards

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채택된 답변

Adam Danz
Adam Danz 22 Aug 2020
편집: Adam Danz 22 Aug 2020
The answer in this link computes segmented averages as you describe except instead of averaging 1:8, 8:15, ... , it averages 1:8, 9:16, ..., .
Solution
To replicate the edges, you just have to add three line.
The full solutions is shown in this demo.
data = 1:22; % Demo data
winSz = 5; % Window size; winSz=5 results in indices of (1:5, 5:9, 9:13, ...)
replications = repmat([2;ones(winSz-2,1)],ceil(numel(data)/(winSz-1)),1);
dataPrep = repelem(data(:),replications(1:numel(data)));
dataPrep(1) = []; % do not duplicate 1st datapoint
% Reshape dataPrep into matrix.
% NOTE: 'dataPrep' must contain a number of element divisibly by 'winSz'.
% Otherwise, 'dataPrep' will be padded with NaN values so that it is
% divisible by 'winSz'.
if rem(numel(dataPrep),winSz)>0
nanAppend = nan(winSz - rem(numel(dataPrep),winSz),1);
else
nanAppend = [];
end
dataMat = reshape([dataPrep; nanAppend], winSz, []);
movingAverage = mean(dataMat,1,'Omitnan');
Results
The original data:
data =
Columns 1 through 20
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Columns 21 through 22
21 22
The blocked version where means are computed over each column
dataMat =
1 5 9 13 17 21
2 6 10 14 18 22
3 7 11 15 19 NaN
4 8 12 16 20 NaN
5 9 13 17 21 NaN
The means (within a 5-element window)
movingAverage =
3 7 11 15 19 21.5
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EldaEbrithil
EldaEbrithil 22 Aug 2020
Ahahah xD

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