defining divideblock function for feedforward net

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nadia
nadia 2013년 1월 7일
i've used 'divideblock' function as follow:
net.divideFcn = 'divideblock'; net.divideParam.trainRatio = 0.6; net.divideParam.valRatio = 0.20; net.divideParam.testRatio = 0.20;
for feedforward neural network. when i run the program, the details of the network will be displayed. the problem is, it display 2 neural network details. the first set will show
net =
Neural Network
. . . .
functions:
adaptFcn: 'adaptwb'
adaptParam: (none)
derivFcn: 'defaultderiv'
divideFcn: 'dividerand'
and the other one shows
functions:
adaptFcn: 'adaptwb'
adaptParam: (none)
derivFcn: 'defaultderiv'
divideFcn: 'divideblock'
divideParam: .trainRatio, .valRatio, .testRatio
. . . .
is it suppose to be like this when we define 'divideblock' as a divide function? i expect it to display only 1 and not both, since i dont need my data to be randomized.
thank you. :)
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Greg Heath
Greg Heath 2013년 1월 7일
편집: Greg Heath 2013년 1월 7일
Post your code.
P.S. Use fitnet for regression and patternnet for classification. Both call feedforwardnet and provide better output info. There is no reason to use feedforwardnet.

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Greg Heath
Greg Heath 2013년 6월 14일
The default 'dividerand' exists at net creation: net = fitnet(H)
Specifying 'divideblock' then replaces it.

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