Hello!
Could you, please, suggest an answer:
How to define function f (x), which for x from -1 to 1, f (x) = 1; and outside these limits f (x) = 0.
Thank in advance!

댓글 수: 3

Rik
Rik 2020년 8월 11일
This is your homework. What have you tried so far? And do you want a normal (or anonymous) function, or a symbolic function?
Viktoriia Buliuk
Viktoriia Buliuk 2020년 8월 11일
I try to define Window function. I have tried with if.
KSSV
KSSV 2020년 8월 11일
Show us your code.

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hosein Javan
hosein Javan 2020년 8월 11일

0 개 추천

function y = f(x)
y = zeros(size(x));
y(abs(x) < 1) = 1;
end

댓글 수: 5

hosein Javan
hosein Javan 2020년 8월 11일
the advantage of such definition is that you can pass inputs to the function as array rather than scalars. it should really help in dealing with fourier transform which requires element-wise product.
hosein Javan
hosein Javan 2020년 8월 11일
however this method could lead to unnecessary computer calculations becasue when you multiply the window function to your signal, the elements that are multiplied eaither by 1 or 0 which is unnecessary. multiplication is for a non-rectangular window function like gaussian,etc,.. . but in the case of rectangular. you only have to select the values of your function that meet the condition by array indexing. if you are planning to do heavy simulation with rectangular window, indexing is more efficient but if it's just a simple calculation function multiplication should be fine.
Rik
Rik 2020년 8월 11일
편집: Rik 2020년 8월 11일
In this case you can simply convert the logical to double:
f=@(x) double(abs(x)<1);
In most other cases you will need multiplication:
%g={x^2 for -1<x<1
% {8 for x>2
% {0 otherwise
g=@(x) ...
x.^2.*(-1<x & x<1)+...
8.*(x>2)+...
0;
hosein Javan
hosein Javan 2020년 8월 11일
ofcourse unless you want to use function file, you need this multiplication only to define your function in anonymous form. correct.
Viktoriia Buliuk
Viktoriia Buliuk 2020년 9월 4일
Thank you very much!

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