Sampling a large matrix using column indices

I am trying to sample a large(17x16602) matrix for use as a kernel for a kernel kmeans algorithm. Because the matrix is very large(and full), I decided sample it randomly. I now have a list of 1000 column indices which I want to use to extract data from my matrix. I have tried all of the simple indexing techniques, but all I am getting are the values within the first row that I want. What I have so far is:
L=length(x);
IDX_RAND=randperm(L);
IDX_SAMP=IDX_RAND(1:1000);
What I want is to use the column values in IDX_SAMP to extract a 17x1000 matrix for use in my kernel. The desired result would return the column value in IDX_SAMP and preserve the trailing 16 rows in that column. Any help or clarification requests are appreciated. Thanks!

 채택된 답변

Walter Roberson
Walter Roberson 2012년 12월 26일

0 개 추천

If you are looking for the value of the same columns for each of the rows, then
x(:, IDX_SAMP)
Note: I advise you to use L = size(x,2) instead of L = length(x) as length() does not always choose the same dimension.

댓글 수: 1

Jacob Moses
Jacob Moses 2012년 12월 26일
Thank you, this is exactly what I needed. And I'll keep in mind using size for this project.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터 및 File Exchange에서 Logical에 대해 자세히 알아보기

제품

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by