# is there a function in matlab that creates a binary repetition coder ?

조회 수: 12(최근 30일)
mary 25 Dec 2012
for example when i enter a sequence 0010110 ;when n=3
the result will be 000000111000111111000

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### 채택된 답변

Azzi Abdelmalek 25 Dec 2012
편집: Azzi Abdelmalek 25 Dec 2012
s='0010110'
out=repmat(s,3,1)
out=out(:)'
%or
s=[0 0 1 0 1 1 0];
out=reshape(repmat(s,3,1),1,[])

#### 댓글 수: 7

표시 이전 댓글 수: 4
Azzi Abdelmalek 25 Dec 2012
a=reshape(out,3,[]);
b=a(1,:)
José-Luis 25 Dec 2012
b=a(1:3:numel(a));
mary 25 Dec 2012
okey it worked .. thanx alot :)

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### 추가 답변(1개)

Nasser M. Abbasi 25 Dec 2012
You did not say what is the class of 0010110, so I assume cell array.
r = {'0' '0' '1' '0' '1' '1' '0'};
n = 3;
reshape(repmat(r,n,1),1,n*numel(r))'
ans =
'0'
'0'
'0'
'0'
'0'
'0'
'1'
'1'
'1'
'0'
'0'
'0'
'1'
'1'
'1'
'1'
'1'
'1'
'0'
'0'
'0'
This is a cell. Now you can do with it any conversion you want.
--Nasser

#### 댓글 수: 2

mary 25 Dec 2012
it is a 1 by n matrix .. by the way can you help me with generating such an array of zeros and ones?? thanx alot
mary 25 Dec 2012
i mean such a matrix of 1 by n dimensions?

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