Produce a legend in for loop that takes entries from an array

Merry Christmas to all of you. I am trying to incorporate a legend in for loop. my code is the following:

s=['T   '; 'Pb  '; 'Pf  '; 'Pc  '; 'Psh '; 'Pito'];
t=cellstr(s);
figure
 for k=1:length(pl(end,end,:))
    for m=1:length(pl(:,end,end))
        subplot(2,3,m) % BUSBAR
        semilogx(dim(1,Nmin:Nmax,k)*1000,pl(m,Nmin:Nmax,k),'linewidth',2)                  
        title(t(k))
        hold all
    end
 end

My idea is simple. I want to have a legend that takes values from an array. So if for example I have six curves per plot, I would like to have one legend with 6 entries. I would like something like that because I change very frequently the number of entries and the entries themselves. To give you more details I would like to build a legend with 4 entries and each entry I would like to say 1cm 2cm 3cm 4cm. But I might change that later to 6 different entries.

For that reason I am trying to use a function from the matlab file exchange legend1.m. You can find this in: http://www.mathworks.in/matlabcentral/fileexchange/39505-legend1-m.

I didn't have any success yet. Can you help me please.

Answer 1

[Matt J]

My idea is simple. I want to have a legend that takes values from an array.

That doesn't require any special files. Here's a simplified example,

    l={'a','b','c'}; 

    figure 
    plot(1:5,1:5,1:5,1:5);
    legend(l{[2,3]});

    figure
    plot(1:5,1:5,1:5,1:5);
    legend(l{[1,3]});

[Matt J]

Giorgos commented:

Thank you. Indeed that is much more simple and efficient. On the other hand what if I want to have a constant character cell in all my legend entries and that is cm and add to it the number from an array and this array would be

l=[1 2 3 4]

so the output in the legend would be:

• 1 cm
• 2 cm
• 3 cm
• 4 cm

[Matt J]

That has nothing to do with plotting. That's just a problem in how to build a certain cell array of strings:

     l=arrayfun(@(i) [num2str(i) ' cm'],1:4,'uni',0 )

Answer 2

[Giorgos Papakonstantinou]

Thank you. Indeed that is much more simple and efficient. On the other hand what if I want to have a constant character cell in all my legend entries and that is cm and add to it the number from an array and this array would be

l=[1 2 3 4]

so the output in the legend would be:

• 1 cm
• 2 cm
• 3 cm
• 4 cm

Answer 3

[Giorgos Papakonstantinou]

Thank you Matt