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parallel loop in matlab

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Abhishek Saini
Abhishek Saini 26 Jul 2020
답변: Edric Ellis 28 Jul 2020
Hi ,
I am new to use parfor in MATLAB. I am trying to convert my for loop in to parfor, but getting problem in varaible definition. Here is the a section of the code where I want to implement parfor. Kindly advice how to run this correctly.
%% matrices initialisation
KB=zeros(sdof,sdof);
KS=zeros(sdof,sdof);
KK=zeros(sdof,sdof);
FF=zeros(sdof,1);
KG=zeros(sdof,sdof);
[DB,DS]=material_mat(E,nu,G,shcof);
parfor i=1:nelem
elecon=elemconn(i,:);
nodes =cor(elecon,1:2);
index1=nodedof(elecon,:).';
index=reshape(index1,1,size(index1,1)*size(index1,2));
[KB_final]=elementstiffness_bending(nodes,DB);
[KS_final,F_final]=elementstiffness_shear(nodes,DS,P);
[KG_final]=geometricstiff(sigma_i,nodes);
KK1=KB_final+KS_final;
[KK,FF,KG] = paral(KK1,F_final,KG_final,index,KK,FF,KG,i);
KB(index,index) = KB(index,index) + KB_final;
end
I am getting problem in defining Kb variable. How to rectify this?

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답변(1개)

Edric Ellis
Edric Ellis 28 Jul 2020
Output variables in parfor loops must be either sliced outputs or reduction outputs. More info here in the doc. In this case, you need KB to be a "reduction" variable since each iteration of your loop computes an increment to that matrix. To fit in with the parfor rules, you cannot index a "reduction" variable, so you need to modify things a little to have each iteration compute a full-sized increment. Something a bit like this
parfor i = 1:nelem
% compute KB_final and index
KB_increment = zeros(sdof);
KB_increment(index,index) = KB_final;
% Use a reduction assignment into KB:
KB = KB + KB_increment;
end

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