timer and counter function query using loops

clc;
clear;
close all;

state = 0;
sequance = 0;
previous_state = 0;

for n = 0 : 15
    time = n ;
    p = 1;
    input = int32(randi([0, 1], [1, p]));
    comparison = isequal(input,previous_state);
    previous_state = input;
   
    if comparison == 0
        state = state + 1;
        sequance = 0;
    else
        %for zz = 0:10
            sequance = sequance + 1;
            %if sequance >= 2
           time = time + (2^sequance/1000);
       % end
        %disp(state);
    end
    fprintf('%f    %f     %f    %f\n',time,input,state,sequance);
end

0.000000    1.000000     1.000000    0.000000
1.000000    0.000000     2.000000    0.000000
2.002000    0.000000     2.000000    1.000000
3.004000    0.000000     2.000000    2.000000
4.008000    0.000000     2.000000    3.000000
5.016000    0.000000     2.000000    4.000000
6.000000    1.000000     3.000000    0.000000
7.002000    1.000000     3.000000    1.000000
8.000000    0.000000     4.000000    0.000000
9.002000    0.000000     4.000000    1.000000
10.000000    1.000000     5.000000    0.000000
11.002000    1.000000     5.000000    1.000000
12.004000    1.000000     5.000000    2.000000
13.008000    1.000000     5.000000    3.000000
14.016000    1.000000     5.000000    4.000000
15.000000    0.000000     6.000000    0.000000

Here, in my program the output in timer is incresing 0.004 msec. after 1 sec. but I want to incerase in particual at same sec. and print at same time.

Please help me, Thank you in advance

[per isakson]

"but I want to incerase in particual at same sec. and print at same time." I don't get what you want. Show an example!

"timer is incresing 0.004 msec" I would say that accourding to your code it's increasing by

( 2^sequance - 2^(sequance-1) )/1000

where

sequance = ( 1, 2, 3, ... )

during sequences when comparison==true which is what your output shows

Answer 1

[Walter Roberson]

I could not figure out your rules based upon your desired output. Here is one approximation that you could adapt further.

state = 0;
sequance = 0;
previous_state = 0;
prob = 0.1;

time = 1;
for n = 0 : 15
    p = 1;
    
    %input = int32(randi([0, 1], [1, p]));
    input = int32(xor(previous_state, rand() < prob));
    comparison = isequal(input,previous_state);
    previous_state = input;
   
    if comparison == 0
        state = state + 1;
        sequance = 0;
        newtime = max(ceil(time), time+1);
    else
        %for zz = 0:10
        
            sequance = sequance + 1;
            if sequance > 9
                newtime = time + 1;
            else
              newtime = time + state/100 + (2^sequance/1000);
            end
       % end
           
        %disp(state);
    end
    fprintf('%10g %10g %10g %10g %10g\n',time,input,state,sequance,comparison);
    time = newtime;
end

fprintf('\n');

[Walter Roberson]

(reminder to myself)