pmtm (Multitaper) calculates PSD from Fourier coefficients as abs(Xx)^2; shouldn't that be Xx.conj(Xx)?

조회 수: 1 (최근 30일)
In MATLAB 7.11.2(R2010b) Service Pack 2, in the Signal Processing Toolbox file pmtm.m (Multitaper), line 232, the current code uses abs(Xx).^2, where XX is the set of raw Fourier coefficients, to eventually calculate the PSD. Shouldn't that be Xx.conj(Xx) since power is defined as the square of the norm of the Fourier coefficients?
% Compute DFT using FFT or Goertzel
[Xx,w] = computeDFT(E(:,1:k).*x(:,ones(1,k)),nfft,Fs);
%Sk = abs(Xx).^2; % OLD CODE HERE
Sk = Xx.*conj(Xx); % AK CHANGE HERE
Thanks, A K

채택된 답변

Wayne King
Wayne King 2012년 12월 13일
편집: Wayne King 2012년 12월 13일
There is no difference between
abs(Z).^2
and
Z.*conj(Z)
for a complex vector. They are equivalent. In fact, for a complex number the modulus (norm) is defined to be the square root of the product of Z and its conjugate.
Just convince yourself for a single complex number
Z = 1+1i;
abs(Z)^2
Z*conj(Z)
  댓글 수: 1
Ajoy
Ajoy 2012년 12월 13일
Of course you are right; sorry, thought abs() returned just the real part; it does actually return the norm. Thanks, A K.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Parametric Spectral Estimation에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by