transformation between different time representations

Hello, I have a vector whose elements are of the kind "hhmmss", representing different times of a certain day. I have to transform them in a decimal number 0.xyzt... representing the fraction of day corresponding to that time. How can I do? Thanks, Elena.

Answer 1

[Azzi Abdelmalek]

 out=datenum(date)

Also look at datestr, datevec

Answer 2

[Peter Perkins]

Elena, if your times are strings, then Azzi's suggestion is the way to go. But if your times are numeric (53221, say, as opposed to '053221'), then you'll need to successively divide by 100 and use floor to get the hours, then similarly get minutes, and the seconds, and then multiply those by 1/24, 1/(24*60), and 1/(24*60*60) and add that up.

Hope this helps.