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FSOLVE requires all values returned by functions to be of data type double.

조회 수: 2 (최근 30일)
Mj
Mj 2020년 7월 9일
Hello. this is my code.it solves the first function and gives the values of x1(i,1).
but it does not go to solving the function of mysubfun1. and stops.
what should i do?
function x1 = supercriticalahmad
for i=1:2
x1(i,1) = fsolve(@mysubfun,0.1);
p2x1(i,1)=sqrt(1-(4.*x1(i,1).^2));
p1x1(i,1)=2.*asin(2.*x1(i,1))+4.*x1(i,1).*sqrt(1-(4.*x1(i,1).^2));
F1(i,1)=(p2x1(i,1)/p2xc(i,1))^(1/2).*(p1xc(i,1)/p1x1(i,1))^(3/2);
end
function xe=hoda
xe(i,1) = fsolve(@mysubfun1,0.1)
EDR(i,1)=xe(i,1)./xc(i,1)
function ff= mysubfun1(xe)
p1xe(i,1)=2.*asin(2.*xe)+4.*xe.*sqrt(1-(4.*xe.^2));
b(i,1)=1/(2.*xc(i,1).*(1+(p1xc(i,1)/(16.*xc(i,1).*p2xc(i,1))))); %b(i,1) haman R/H mib(i,1)ashad.
a0(i,1)=1;
a1(i,1)=(1/2).*b(i,1);
a2(i,1)=(1/8).*((b(i,1).^2)+4);
a3(i,1)=(1/16).*((b(i,1).^3)-(4.*b(i,1)));
a4(i,1)=(5/128).*((b(i,1).^4)-(8/5).*b(i,1).^2+(16/5));
a5(i,1)=(7/256).*(b(i,1).^5-(8/7).*b(i,1).^3-(16/7).*b(i,1));
a6(i,1)=(21/1024).*((b(i,1).^6)-(20/21).*b(i,1).^4-(16/21).*b(i,1).^2+(64/21));
a7(i,1)=(231/14336).*((b(i,1).^7)-(28/33).*b(i,1).^5-(112/231).*b(i,1).^3-(448/231).*b(i,1));
p3x1(i,1)=((a0(i,1).*xc(i,1))-(a1(i,1).*(xc(i,1).^2))-((4/3).*a2(i,1).*(xc(i,1).^3))...
-((8/4).*a3(i,1).*(xc(i,1).^4))-((16/5).*a4(i,1).*(xc(i,1).^5))-((32/6).*a5(i,1).*(xc(i,1).^6))...
-((64/7).*a6(i,1).*(xc(i,1).^7))-((128/8).*a7(i,1).*(xc(i,1).^8)));
ff=(32.*sqrt(2).*p1xe(i,1).*p3x1(i,1).*((x1(i,1)+(F1(i,1).^2.*p1x1(i,1))...
/(16.*p2x1(i,1))).^(1/2)).*(p2x1(i,1).^(1/2)./p1x1(i,1).^(5/2)))-F1(i,1);
end
end
disp('xc=')
disp(xc)
disp('Qstar=')
disp(Qstar)
disp('sc=')
disp(sc)
disp('x1=')
disp(x1)
disp('F1=')
disp(F1)
%disp('xe=')
%disp(xe)
%disp('EDR=')
%disp(EDR)
function f = mysubfun(x1)
Q=[0.000788
0.000866];
s=0.022;
n=0.012;
D=0.128;
xc=[0.123
0.131];
p1xc(i,1)=2.*asin(2.*xc(i,1))+4.*xc(i,1).*sqrt(1-(4.*xc(i,1).^2));
p2xc(i,1)=sqrt(1-(4.*xc(i,1).^2));
p1x1(i,1)=2.*asin(2.*x1)+4.*x1.*sqrt(1-(4.*x1.^2));
Qstar(i,1)=(p1xc(i,1).^(3/2))./(16.*sqrt(2).*p2xc(i,1).^(1/2));
Ac(i,1)=(D.^2/8).*p1xc(i,1);
Pc(i,1)=D.*(1+asin(2.*xc(i,1)));
Rc(i,1)=Ac(i,1)./Pc(i,1);
sc(i,1)=(n.^2.*Q(i,1).^2)./(Ac(i,1).^2.*Rc(i,1).^(4/3));
f=((p1xc(i,1)./p1x1(i,1)).^(10/3).*((1+asin(2.*x1))./(1+asin(2.*xc(i,1)))).^(4/3))-s/sc;
end
end

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