evaluate whether a condition is met

Hi all, I have to evaluate whether a condition is met: this is the basic method:

if a1 < b1 < a2
     disp ('ok')
     else disp ('error')
end

If I had n "b" and n+1 "a" I should write n if or is there a way to simplify it? if so how? thank you very much

[Matt J]

I assume you really mean

   if a1 < b1 & b1 < a2
       disp ('ok')
       else disp ('error')
  end

Answer 1

[Matt J]

Assuming size(a) is [1,n+1] and size(b) is [1,n]

 if a(1:end-1)<b  &  b<a(2:end)

Answer 2

[Max]

Perfect! Now, for example, If during the second cycle the condition is not satisfied, the overall result will be error; it is possible to print statements that do not meet this condition?

I hope I was clear ;)

Max

[Matt J]

disp(find(~(a(1:end-1)<b  &  b<a(2:end))))

Answer 3

[Max]

Sorry Matt J, I read only now you precondition that

a1 < b1 & b1 < a2

in my situation I have to evaluate if a value is in-range or is out-range. the value have to be in its range

For example:

a_1 < b_1 < a_2

a_2 < b_2 < a_3

a_n < b_n < a_n+1

etc.

and

b_1 = a_1 + x_1

b_2 = a_2 + x_2

b_n = a_n + x_n

etc

x is a column-vector of n elements;

is correct if I do:

if a(1:end-1) < (a(1:end-1) + x(1:end) ) < a(2:end-1)

[Matt Fig]

Please stop posting new "Answers" to your question. None of these are answers to the original question. Post in the comments if you have follow-up questions.

[Max]

Sorry...

[Matt J]

is correct if I do: if a(1:end-1) < (a(1:end-1) + x(1:end) ) < a(2:end-1)

No. Triple inequality statements in MATLAB will not do what you expect. That was the point of my earlier Comment. For example, I don't think you expect the following to return false, but it does:

    >> 0<.5<1

    ans =

         0

Contrast this with,

    >> (0<.5) & (0.5<1)

    ans =

         1

[Max]

of course, you're right ... I was wrong to do the math...

you're very very talented...

a curiosity ... if, instead, I wanted to print also the statements that verify the condition, which is the command??

thanks for the constant assistance

Max

[Matt J]

You should post this as a new question and make it clearer. We would probably need a specific example showing the output that you want.

[Max]

ok ;)