imshow produces error when used in subplot

조회 수: 4 (최근 30일)
F Sp
F Sp 2020년 6월 6일
댓글: F Sp 2020년 6월 7일
Hello,
I had a working code using:
figure, imshow(I);
Then I wanted to put all the displayed images into one figure using subplot in this way:
figure;
h = [];
h(1) = subplot(2,4,1); etc.
and calling the image via:
imshow(I,'Parent', h(2))
The problem is that this now produces the error:
"Unable to perform assignment because dot indexing is not supported for variables of this type.
Error in images.internal.basicImageDisplay (line 78)
ax_handle.Colormap = map;
Error in imshow (line 330)
hh = images.internal.basicImageDisplay(fig_handle,ax_handle,..."
Also the image now appears blue and yellow instead of black and white.
Being new to MatLab I can only assume something went wrong with the colormap interfering with multiple images in one figure.
Any help would be appreciated a lot :)

채택된 답변

Ameer Hamza
Ameer Hamza 2020년 6월 6일
From your code, it is not clear how did you assign the 2nd element of vector h. However, I recommend initializing 'h' with 'gobjects'.
Replace
h = [];
with
h = gobjects;
  댓글 수: 3
Image Analyst
Image Analyst 2020년 6월 6일
What page gave that incorrect information? Not this one.
F Sp
F Sp 2020년 6월 7일
somewhere on MatLab Answers, of course not in this particular question. Thank you guys

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추가 답변 (1개)

Image Analyst
Image Analyst 2020년 6월 6일
편집: Image Analyst 2020년 6월 6일
You do not need to initialize h to anything, not [] nor gobjects. This works perfectly fine:
figure;
h = []; % Unnecessary.
h(1) = subplot(2,4,1);
% and calling the image via:
I = imread('peppers.png');
imshow(I,'Parent', h(1))
Just make sure you haven't assigned h to anything in advance, like h is not already a cell array or structure or some other complicated non-numerical variable. If h does already exist when you get to h=[], then it might be a mistake to use the same variable h because setting it to null would blow it away and if you ever needed that original h again you would not have it anymore.
Just make sure whatever index you're using in h exists, like you can't use h(2) if you haven't called h(2) = subplot yet.

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