Given matrices XX and YY of sizes 3X3, how can I generate the following matrix: [XX(1,1) YY(1,1); XX(1,2) YY(1,2)... ?

Given matrices XX and YY of sizes 3X3, how can I generate the following matrix:
[XX(1,1) YY(1,1); XX(1,2) YY(1,2);XX(1,3) YY(1,3); XX(2,1) YY(2,1); XX(2,2) YY(2,2); XX(2,3) YY(2,3); XX(3,1) YY(3,1); XX(3,2) YY(3,2); XX(3,3) YY(3,3)]
I mean of course, without writing it explicitly and without loops.
Thanks!!

 채택된 답변

or:
XX = magic(3);
YY = eye(3);
XX_trans = transpose(XX);
YY_trans = transpose(YY);
out = [XX_trans(:) YY_trans(:)];

추가 답변 (2개)

Matt Fig
Matt Fig 2012년 11월 15일
편집: Matt Fig 2012년 11월 15일
For example:
XX = magic(3);
YY = cumsum(ones(3));
% Your requested matrix.
ZZ = [reshape(XX.',[],1) reshape(YY.',[],1)]
C.J. Harris
C.J. Harris 2012년 11월 15일
편집: C.J. Harris 2012년 11월 15일
This is one way of doing it - expanding on my answer to your previous question:
XX = magic(3);
YY = eye(3);
out = unique(nchoosek([1:3, 1:3], 2), 'rows');
XX_Array = arrayfun(@(x)[(XX(out(x,1),out(x,2)))], 1:size(out,1))';
YY_Array = arrayfun(@(x)[(YY(out(x,1),out(x,2)))], 1:size(out,1))';
combArray = [XX_Array YY_Array];

카테고리

도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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질문:

Gil
2012년 11월 15일

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