필터 지우기
필터 지우기

For loop using bin2dec conversion

조회 수: 1 (최근 30일)
Darshan Manjunathrao Chawan
Darshan Manjunathrao Chawan 2020년 5월 30일
input=[1 1 0 1 0 0 1 0 ]; %input bit
x1=bin2dec(num2str(11)); %converting number to characters
x2=bin2dec(num2str(01));
x3=bin2dec(num2str(00));
x4=bin2dec(num2str(10));
xx=[x1,x2,x3,x4];
This is my code, I don't want to use individual bin2dec conversion. How can I put it in 'for loop'?

채택된 답변

Stephen23
Stephen23 2020년 5월 30일
편집: Stephen23 2020년 5월 30일
This is MATLAB, you don't need a for loop!
Method one: mtimes:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = pow2(N-1:-1:0)*reshape(V,N,[])
X =
3 1 0 2
Method two: bin2dec:
>> V = [1,1,0,1,0,0,1,0];
>> N = 2;
>> X = bin2dec(reshape(sprintf('%u',V),N,[]).');
X =
3
1
0
2
  댓글 수: 3
Stephen23
Stephen23 2020년 5월 30일
"But can't I put it in for loop to determine individual values"
Of course, you can use a loop if you want to. Try it.
Darshan Manjunathrao Chawan
Darshan Manjunathrao Chawan 2020년 5월 30일
Can you please help me with that?

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by