hi, im having trouble with finding the string at the end of the code. the error seems to be in the last part. can you please help me resolve it?
stream_n = reshape (msg_error_checked', n, [])';
info_stream = stream_n (:, 1: k);
question = dec2bin (char (info_stream'+ '0' ));
real = '';
%%real = strcat( real,char(bi2de(question,'left-msb')));

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Sanjay Ravichandran
Sanjay Ravichandran 2020년 5월 23일
This is a extension of my question:
https://www.mathworks.com/matlabcentral/answers/531318-converting-binary-characters-into-a-char-error?s_tid=prof_contriblnk

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답변 (1개)

Ameer Hamza
Ameer Hamza 2020년 5월 23일
편집: Ameer Hamza 2020년 5월 23일

0 개 추천

Something like this?
x = [1 0 0 1 1 1 0 0 1 1];
y = strrep(num2str(x), ' ', '')
Result
y =
'1001110011'

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Aravind chockaiaah KANNAN
Aravind chockaiaah KANNAN 2020년 5월 23일
thanks for the reply. but i cant able to get the binary itself.
Aravind chockaiaah KANNAN
Aravind chockaiaah KANNAN 2020년 5월 23일
i realised that my question was unclear. for additional info.....i have attached a plot, from which i got the values from. i'm trying to use (k,n) = (4,7). but im getting an error saying....... https://www.mathworks.com/matlabcentral/answers/531318-converting-binary-characters-into-a-char-error?s_tid=prof_contriblnk. the same.

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카테고리

도움말 센터File Exchange에서 Characters and Strings에 대해 자세히 알아보기

질문:

2020년 5월 23일

편집:

2020년 5월 25일

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