I want to plot this function
f(x)=sinx, 0<=x<1
0, elsewhere
Then i wrote code for this function
x=-5:0.01:5;
if 0<=x<1
f=sinx;
else
f=0;
end
plot(x,y);
but when i plotted this code then, there was nothing on the graph
what's wrong on this code? and how can i plot this function?

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Stephen23
Stephen23 2020년 5월 16일
편집: Stephen23 2020년 5월 16일

0 개 추천

"what's wrong on this code?"
  • if does not change subsets of an array like that (you would need to use if inside of a loop).
  • You also need to read the if documentation to know how it behaves with non-scalar conditions.
  • MATLAB does not have ternary logical operators like 0<=x<1. What you wrote is equivalent to (0<=x)<1 which is equivalent to either 0<1 or 1<1 (but the first case will return true when you don't expect it to).
The MATLAB way is to use logical indexing, e.g.:
>> x = -5:0.01:5;
>> y = sin(x);
>> y(x<0|x>=1) = 0;
>> plot(x,y)

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akdlcnd3gh
akdlcnd3gh 2020년 5월 17일
Thank you for your reply.
I think I still lack an understanding of how matlab works
Stephen23
Stephen23 2020년 5월 17일
Low-level languages: loops and ifs
High-level languages: functions and comprehensions
MATLAB: arrays and indexing
akdlcnd3gh
akdlcnd3gh 2020년 5월 17일
thank you so much!
I'll read carefully

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