Need help with difference equation (continuous-time system)

Hello, How to solve the equation in Matlab?

y''(t)+5*y'(t)+6y(t)= u(t)

y'(0)=y(0)=0

u(t) = 1(t) or u(t)= t*1(t)

I found the solution by hand through the transformation of Laplace, it came like this:

y(t)= 1/6 - exp(-2*t)/2 + exp (-3*t) for u(t)=1(t)

[Azzi Abdelmalek]

Do you need a numeric solution or symbolic?

[Titus Edelhofer]

Since he found the solution by hand, I guess the numerical solution is searched for ...? BTW you want to solver a differential equation, not a difference equation ...

Answer 1

[Rajiv Singh]

[y,t] = step(tf(1,[1 5 6]))

[Alex]

Thank you)

Answer 2

[Titus Edelhofer]

Hi,

you will need to convert your second order problem to a system of first order equations (by setting y1=y, y2=y'). Then use ode45 to solve the system.

Titus