How do I get this graph?

조회 수: 1 (최근 30일)
Joo Seo Lee
Joo Seo Lee 2020년 4월 25일
댓글: Ameer Hamza 2020년 4월 25일
I want to get the graph of n and x(n) on x(n+1)=2.5*x(n)*(1-x(n)), where x(1)=0.9
I wrote
x(1)=0.9;
for n = 1:100,
x(n+1)=x(n)*(1-x(n))*2.5
plot (x(n),n)
end
and my plot is empty

채택된 답변

Ameer Hamza
Ameer Hamza 2020년 4월 25일
편집: Ameer Hamza 2020년 4월 25일
Try this
x(1)=0.9;
for n = 1:100
x(n+1)=x(n)*(1-x(n))*2.5;
end
plot(x)
In your code, you are just plotting one point at a time and then overwriting it with a new plot statement.
  댓글 수: 2
Joo Seo Lee
Joo Seo Lee 2020년 4월 25일
thanks!
Ameer Hamza
Ameer Hamza 2020년 4월 25일
Glad to be of help.

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추가 답변 (1개)

Sriram Tadavarty
Sriram Tadavarty 2020년 4월 25일
Hi Joo,
The code is calculating as you expected, but not plotting the same because, the plot is getting overwritten with the latest value of x(n).
You can try the following code modifications:
Option 1:
Use hold on to update the figure for each iteration
x(1)=0.9;
for n = 1:100
x(n+1)=x(n)*(1-x(n))*2.5;
plot(n,x(n),'*') % Plotting at each point, line doesn't help, so try symbols
hold on
end
Option 2:
Plot x after the computation
x(1)=0.9;
for n = 1:100
x(n+1)=x(n)*(1-x(n))*2.5;
end
plot(x)
Hope this helps.
Regards,
Sriram

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