How can I solve this error when I use Trapz ?
    조회 수: 2 (최근 30일)
  
       이전 댓글 표시
    
I keep getting this error when I run my program.
err = 1-y;              %Define error signal
t = 0 : 0.01 :30;      
ise = trapz (1,err.^2);
-------
Error using trapz (line 47)
Dimension argument must be a positive integer scalar within indexing range. 
Undefined operator '.^' for input arguments of type 'timeseries'.
y here is output data from a block diagarm simulink. 
any solutions?
댓글 수: 2
채택된 답변
  Ameer Hamza
      
      
 2020년 4월 17일
        Try this
err = 1 - y.Data;              %Define error signal   
ise = trapz(y.Time, err.^2);
댓글 수: 2
추가 답변 (0개)
참고 항목
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
