# Function like "find" but for lines

조회 수: 3(최근 30일)
steve Brian 7 Apr 2020
댓글: steve Brian 7 Apr 2020
Hi everyone, I need a function that starts counting every element in an array (each line), and when it finds 0, it can skip it.
ex: A = [6 5 0 1; 3 1 0 0; 12 0 100 20]
newA = [ 1 2 4 5 6 9 11 12]
I was trying something like this:
k = 0;
colind = 1:numel(A);
colind(A!=k)
But it only takes me each column in the matrix.
wrong: newA = [1 2 3 4 5 9 10 12]
I want to count my elements on each line of the matrix. A little help please! :)

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### 채택된 답변

Stephen Cobeldick 7 Apr 2020
>> B = find(A.').'
B =
1 2 4 5 6 9 11 12

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표시 이전 댓글 수: 1
Stephen Cobeldick 7 Apr 2020
>> [B,~] = find(A.');
>> B = B.' % optional
B =
1 4 1 2 4 1 3 4 5 3 4 5
Birdman 7 Apr 2020
Good for us to learn :)
steve Brian 7 Apr 2020
Yeah, thanks a lot :D

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### 추가 답변(2개)

Birdman 7 Apr 2020
B=reshape(A.',1,[]);
C=(1:numel(A)).*(B~=0);
C=C(C~=0)

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Ameer Hamza 7 Apr 2020
편집: Ameer Hamza 7 Apr 2020
new_A = find(A')

#### 댓글 수: 2

steve Brian 7 Apr 2020
And if i want to reset count on each line?
something like this:
A = [100 0 0 2 0; 3 4 0 5 0; 6 0 7 8 9; 0 0 10 11 0; 0 0 0 0 12]
newA= [1 4 1 2 4 1 3 4 5 3 4 5]
Ameer Hamza 7 Apr 2020
The functionality of find function is the same, so
[new_A,~] = find(A');

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