Function like "find" but for lines

Hi everyone, I need a function that starts counting every element in an array (each line), and when it finds 0, it can skip it.

ex: A = [6 5 0 1; 3 1 0 0; 12 0 100 20]

newA = [ 1 2 4 5 6 9 11 12]

I was trying something like this:

k = 0;

colind = 1:numel(A);

colind(A!=k)

But it only takes me each column in the matrix.

wrong: newA = [1 2 3 4 5 9 10 12]

I want to count my elements on each line of the matrix. A little help please! :)

Answer 1

[Stephen23]

>> B = find(A.').'
B =
    1    2    4    5    6    9   11   12

[steve Brian]

And if i want to reset count on each line?

something like this:

A = [100 0 0 2 0; 3 4 0 5 0; 6 0 7 8 9; 0 0 10 11 0; 0 0 0 0 12]

newA= [1 4 1 2 4 1 3 4 5 3 4 5]

[Stephen23]

>> [B,~] = find(A.');
>> B = B.' % optional
B =
   1   4   1   2   4   1   3   4   5   3   4   5

[Birdman]

Good for us to learn :)

[steve Brian]

Yeah, thanks a lot :D

Answer 2

[Birdman]

B=reshape(A.',1,[]);
C=(1:numel(A)).*(B~=0);
C=C(C~=0)

Answer 3

[Ameer Hamza]

new_A = find(A')

[steve Brian]

And if i want to reset count on each line?

something like this:

A = [100 0 0 2 0; 3 4 0 5 0; 6 0 7 8 9; 0 0 10 11 0; 0 0 0 0 12]

newA= [1 4 1 2 4 1 3 4 5 3 4 5]

[Ameer Hamza]

The functionality of find function is the same, so

[new_A,~] = find(A');