Hello
I have a code like this
for k=1:3
%something
if %one condition
d=d-2
if %the other condition
d=d+3
end
end
end
Basically I've written a loop in which I change the value of d
I have 3 iterations and 3 values of d.
I want to plot the values of d against the iteration's number, so that the x axis will be the iteration numbers and the y axis will be the values of d. How can I do this?
I've searched similar questions but haven't found like this one.
Thank you

댓글 수: 6

Possibly it will work to save the values of d?
d = zeros(4,1);
d(1) = 0; % put initial value for d here
for k=1:3
%something
if %one condition
d(k+1)=d(k)-2
elseif %the other condition
d(k+1)=d(k)+3
end
end
plot(1:3,d(2:end))
That is great, but it gives me errors. I have an .m file like this
%something......
d=zeros(p+1,1)
d(1)=0.2
p=3
for k=1:p
%parameterized function
a=2; b=2; c=0.5; e=0.5;
u_g = @(x, x_e, N)(-0.5*a*x.^2+b*(x-x_e)-c*N+e*u_p(x,x_e,N, d(k)));
%something......
p=(u_p(Z(:,1), Z(:,3), Z(:,2),d(k)).');
if %one condition
d(k+1)=d(k)-2
elseif %the other condition
d(k+1)=d(k)+3
end
end
plot(1:p,d(2:end))
and I have one function file
function u=u_p(x,x_e,N,d)
u = -(x-x_e).^2+N.*d(k);
end
can I change the value of d in function file or in the loop? I want to change it in every iteration and then make my calculations based on d's new value. but there are some errors like this
Undefined function or variable 'k'.
Error in u_p (line 3)
u = -(x-x_e).^2+N.*d(k);
Error in game>@(x,x_e,N)(-0.5*a*x.^2+b*(x-x_e)-c*N+e*u_p(x,x_e,N,d(k)))
Error in game (line 36)
g=(u_g(Z(:,1),Z(:,3), Z(:,2) ).');
>>
Rik
Rik 2020년 4월 3일
Since you are providing only one value of d to your subfunction you don't need to index it again.
Ani Asoyan
Ani Asoyan 2020년 4월 3일
so should I delete all the indexes or only the index in the function? that doesn't work either way
If you indeed call your function with this
p=u_p(Z(:,1), Z(:,3), Z(:,2),d(k)).';
then your function should look like this
function u=u_p(x,x_e,N,d)
u = -(x-x_e).^2+N.*d;
end
Ani Asoyan
Ani Asoyan 2020년 4월 3일
편집: Ani Asoyan 2020년 4월 3일
I got it ! Thank you sooo much!!

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

질문:

2020년 4월 2일

편집:

2020년 4월 3일

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