Processing 2D into 3D matrix

조회 수: 4(최근 30일)
Minas Emiris
Minas Emiris 2020년 4월 1일
댓글: Minas Emiris 2020년 4월 1일
Hi all.
I have a matrix (phi), say of 1502 rows (harmonic) by 10 columns (observations), where the i,j th element represents the phase of the ith harmonic of the jth observation; say the name of the matrix is X;
I need to find the modeshape corresponding to each harmonic; say y = sin(x + phi(i,j)), where x is a position vector, say x = 0:1:11 (11 position elements);
But since each of these modeshapes has its own corresponding 11 'y' values, what I need is a 3D matrix with size 1502x10x11 with all the modeshape values. How can I use the 2D matrix phi to get the 3D matrix (Modeshapes) that I want?
I tried the following code, which gives a better indication of what I need but it didn't work.
modeshapes = zeros(1502,10,11)
x = 0:1:11
for i = 1:1502
for j = 1:10
modeshapes(i,j,:) = sin(phi(i,j)+x)

채택된 답변

Andrei Bobrov
Andrei Bobrov 2020년 4월 1일
modeshapes = sin(phi + reshape(x,1,1,[]));
  댓글 수: 1
Minas Emiris
Minas Emiris 2020년 4월 1일
Thank you very much, this works.

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추가 답변(1개)

J Chen
J Chen 2020년 4월 1일
You need to change the following statement
x = 0:1:11
x has 12 elements but the modeshapes array only allows 11 elements in the third dimension.
  댓글 수: 2
Minas Emiris
Minas Emiris 2020년 4월 1일
Pardon, it's x = 0:1:10; but it's not because of what you're saying.

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